What is the area (in $$cm^2$$) of the circumcircle of a triangle whose sides are 6 cm, 8 cm and 10 cm respectively?
Circumradius of triangle is calculated by formula -
R = abc / √[(a+b+c)(a+b-c)(a-b+c)(-a+b+c)]
R = 6 × 8 × 10 / √[(6+8+10)(6+8-10)(6-8+10)(-6+8+10)]
R = 480 / √(24 × 4 × 8 × 12)
R = 480 / √(96×96)
R = 480 / 96
R = 5 cm
So, area of circumcircle=$$πr^2$$=(22/7)×25=550/7 .
B is correct choice.
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