For the chemical reaction $$N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$$ the correct option is:

A

$$-\frac{d[N_2]}{dt} = 2 \frac{d[NH_3]}{dt}$$

B

$$-\frac{d[N_2]}{dt} = \frac{1}{2} \frac{d[NH_3]}{dt}$$

C

$$3\frac{d[H_2]}{dt} = {2} \frac{d[NH_3]}{dt}$$

D

$$-\frac{1}{3}\frac{d[H_2]}{dt} = -\frac{1}{2} \frac{d[NH_3]}{dt}$$