Question 24

Find the value of following expression $$\log\sin 40^\circ \log \sin 41^\circ --- \log \sin 99^\circ \log \sin 100^\circ$$

Solution

= $$\log\sin 40^\circ \log \sin 41^\circ..... \log \sin 90^\circ...... \log \sin 99^\circ \log \sin 100^\circ$$

We know that $$sin 90^\circ$$ = 1. And $$\log 1 = 0$$

= $$\log\sin 40^\circ \log \sin 41^\circ..... 0...... \log \sin 99^\circ \log \sin 100^\circ$$

Anything multiplied by 0 is 0.

Hence, option B is the answer.

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