Sum of the,perimeter of Square2 and Square1, is 80 cm. If the side of Square2, is 3 times that of Square1, what is the area of the Square2 ? (in cm )
Let the side of Square1 = a cm
=> Side of Square2 = 3a cm
Sum of perimeter of both squares
=> $$(4 \times a) + (4 \times 3a) = 80$$
=> $$4a + 12a = 80$$
=> $$a = \frac{80}{16} = 5$$
=> Side of Square2 = 5 * 3 = 15 cm
$$\therefore$$ Area of Square2 = $$(15)^2$$
= $$225 cm^2$$
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