If the distance of the point P(1, -2, 1) from the plane $$x + 2y - 2z = \alpha$$, where $$\alpha > 0$$, is 5, then the foot of the perpendicular from P to the plane is

A

$$\left(\frac{8}{3}, \frac{4}{3}, -\frac{7}{3}\right)$$

B

$$\left(\frac{4}{3}, -\frac{4}{3}, \frac{1}{3}\right)$$

C

$$\left(\frac{1}{3}, \frac{2}{3}, -\frac{10}{3}\right)$$

D

$$\left(\frac{2}{3}, -\frac{1}{3}, -\frac{5}{2}\right)$$