Question 23

$$\dfrac{x}{y} = \dfrac{1}{3}$$, then $$\dfrac{x^{2} + y^{2}}{x^{2} - y^{2}}$$

Solution

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Given that x/y = 1/3 => y = 3x.

Substituting this in the given fraction, we get:

$$\dfrac{\left(x^2+\left(3x\right)^2\right)}{\left(x^2-\left(3x\right)^2\right)}=\dfrac{\left(10x^2\right)}{\left(-8x^2\right)}=-\dfrac{10}{8}=-\dfrac{5}{4}$$

=> Option-A

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