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A bullet moving horizontally at $$v$$ strikes a stationary block lying on a smooth horizontal surface and gets embedded in it. The block moves at $$V$$ after the bullet strikes it. Find the ratio of masses of the bullet and the block.
Correct Answer: 0
PLACEHOLDER ANSWER - the answer is an expression in $$v$$ and $$V$$. By conservation of momentum, $$mv = (m + M)V$$, so $$m(v - V) = MV$$. The ratio of the masses of bullet and block is $$\frac{m}{M} = \frac{V}{v - V}$$.
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