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Question 227
What will come in the place of both question marks (?) in the following question?
$$\frac{(?)^{1.8}}{32}=\frac{16}{(?)^{1.2}}$$
Solution
Let the number in the question mark be '$$x$$'
So, $$\frac{x^{1.8}}{32}=\frac{16}{x^{1.2}}$$
So, $$x^{1.8+1.2}=32*16=8^3$$
So, $$x^3 = 8^3$$
Hence, $$x=8$$
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