The number of solutions of the pair of linear equations x + 2y — 8 = 0 and 2x + 4y = 16 is
Correct option is d ..infinetly many
X+2y-8=0
2x+4y-16=0
here, a1= 1 , b1=2, c1= -8
a2=2, b2=4, c2= -16
so, $$\frac{a1}{a2}$$= $$\frac{1}{2}$$ $$\frac{b1}{b2}$$ = $$\frac{2}{4}$$ = $$\frac{1}{2}$$ , $$\frac{c1}{c2}$$ = $$\frac{-8}{-16}$$ = $$\frac{1}{2}$$
since ,$$\frac{a1}{a2}$$ =$$\frac{b1}{b2}$$ =$$\frac{c1}{c2}$$. It will have infinitely many solutions.
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