Question 22

In the adjoining figure, ABCD is a cyclic quadrilateral. If AB is a diameter, BC = CD and $$\angle ABD = 40^\circ$$, find the measure of $$\angle DBC$$.

Solution

Since AB is the diameter $$\angle\ ADB\ =\ 90^0$$

Which gives $$\angle\ DAB\ =\ 50^0$$

ABCD is cyclic quadrilateral so $$\angle\ A+\angle\ C\ =\ 180^0$$

Thus $$\angle\ DCB\ =\ 130^0$$

In$$\bigtriangleup\ $$ BCD, 2x+130 = 150

$$x\ =\ 25^0$$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Data Interpretation Questions SNAP Logical Reasoning Questions

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests