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Question 21

$$N$$ is a two-digit number. When $$6$$ is added to the tens digit and $$2$$ is subtracted from the units digit, we get a two-digit number which is equal to $$3N$$. Then $$N$$ is ______.


Correct Answer: 29

Solution

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Let $$N=10a+b$$. The new number is $$10(a+6)+(b-2)=N+58$$, and it equals $$3N$$. Hence $$N+58=3N$$, so $$N=29$$.

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