Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
$$ABCD$$ is a quadrilateral. $$AB$$ is parallel to $$CD$$ and $$AB>CD$$. If $$AD=AB=BC$$ and $$\angle ADC=140^\circ$$, then the measure of $$\angle CAB$$ is ______ degrees.
Correct Answer: 70
Since $$AB\parallel CD$$, the consecutive interior angles give $$\angle DAB=180^\circ-140^\circ=40^\circ$$. Also, $$AD=BC$$ makes the trapezium isosceles, so $$\angle ABC=40^\circ$$. In triangle $$ABC$$, $$AB=BC$$, so if $$\angle CAB=\angle ACB=x$$, then $$2x+40^\circ=180^\circ$$ and $$x=70^\circ$$.
_1.webp)
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
