RBI Grade B 4 Sep 2016

Direction (26-30) : study the table and answer the given question

Note : few data are missing (indicated by —) You need to calculate the value based on given data . if required, to answer the given questions

Let females in village A = $$x$$

=> Females in village C = $$x$$

Literate females in village A = $$\frac{70}{100} \times x = \frac{7x}{10}$$

=> Graduate females in village A = $$\frac{40}{100} \times \frac{7x}{10}$$

= $$\frac{7x}{25}$$

Literate females in village C = $$\frac{72}{100} \times x = \frac{18x}{25}$$

=> Graduate females in village C = $$\frac{20}{100} \times \frac{18x}{25}$$

= $$\frac{18x}{125}$$

$$\therefore$$ Required ratio of number of non-graduate females (including illiterate females) in villages A and C

= $$(x - \frac{7x}{25}) : (x - \frac{18x}{125})$$

= $$(\frac{18x}{25}) : (\frac{107x}{125})$$

= $$90 : 107$$

In village E,

Let number of males = $$x$$

and Number of females = $$y$$

=> Total literate population = $$\frac{70}{100} (x + y)$$

Literate males = $$\frac{70}{100} \times x$$

Literate females = $$\frac{70}{100} \times y$$

Literate males who are graduates = $$\frac{40}{100} \times \frac{7x}{10} = \frac{7x}{25}$$

Literate females who are graduates = $$\frac{40}{100} \times \frac{7y}{10} = \frac{7y}{25}$$

$$\therefore$$ Required % = $$\frac{(\frac{7x}{25}) + (\frac{7y}{25})}{x + y} \times 100$$

= $$\frac{7}{25} \times 100 = 28 \%$$

In village B,

Let number of males = $$x$$

and Number of females = $$y$$

=> Total literate population = $$\frac{61}{100} (x + y)$$

Literate males = $$\frac{64}{100} \times x$$

Literate females = $$\frac{56}{100} \times y$$

=> $$\frac{64x}{100} + \frac{56y}{100} = \frac{61}{100} (x + y)$$

=> $$64x + 56y = 61x + 61y$$

=> $$64x - 61x = 61y - 56y$$

=> $$3x = 5y$$

=> $$\frac{x}{y} = \frac{5}{3}$$

$$\therefore$$ Required % = $$\frac{5 - 3}{5} \times 100$$

= $$2 \times 20 = 40 \%$$

REASONING