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If the equation $$a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x = 0, a_1 \neq 0, n \geq 2$$, has a positive root $$x = \alpha$$, then the equation $$na_n x^{n-1} + (n - 1) a_{n-1} x^{n-2} + \ldots + a_1 = 0$$ has a positive root, which is
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