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Question 20

The units digit of $$5^{2018} - 3^{2018}$$ is

Powers of 5 always end in 5. Powers of 3 cycle with units digits 3, 9, 7, 1 in period 4, and since $$2018=4\times504+2$$, $$3^{2018}$$ ends in the same digit as $$3^2$$, which is 9. Subtracting requires a borrow, giving units digit $$15-9=6$$.

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