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Question 19

Sushant wrote a two digit number. He added 5 to the tens digit and subtracted 3 from the unit digit of the number and got a number equal to twice the original number. The original number is

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With tens digit $$t$$ and units digit $$u$$, the number is $$10t+u$$ and the new number is $$10(t+5)+(u-3)=10t+u+47$$. Setting this equal to twice the original gives $$10t+u+47=2(10t+u)$$, so $$10t+u=47$$. The original number is 47.

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