Following gates section is connected in a complete suitable circuit.

For which of the following combination, bulb will glow (ON) :

A DC bulb glows when a potential difference exists between its two terminals ($$Y_1 \neq Y_2$$).

$$Y_1 = \overline{\bar{A} + \overline{B \cdot C}} = A \cdot B \cdot C$$

$$Y_2 = \bar{D}$$

Option A: $$A=0, B=0, C=0, D=1 \implies Y_1 = 0, Y_2 = 0 \implies Y_1 = Y_2$$, bulb does not glow.
Option B: $$A=0, B=1, C=1, D=1 \implies Y_1 = 0, Y_2 = 0 \implies Y_1 = Y_2$$, bulb does not glow.
Option C: $$A=1, B=0, C=0, D=0 \implies Y_1 = 0, Y_2 = 1 \implies Y_1 \neq Y_2$$, bulb glows.
Option D: $$A=1, B=1, C=1, D=0 \implies Y_1 = 1, Y_2 = 1 \implies Y_1 = Y_2$$, bulb does not glow.