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$$\text{Output of NAND gate} = \overline{A \cdot A} = \bar{A}$$
$$\text{Output of OR gate} = \bar{A} + B$$
$$Y = \overline{\bar{A} + B} = \overline{\overline{A}} \cdot \bar{B} = A \cdot \bar{B}$$
$$Y$$ is 1 for $$A =$$ and $$B = 0$$
Hence, $$Y = 1$$ for intervals $$(0,1)$$ and $$(4,5)$$, and $$0$$ elsewhere.
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