JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
$$\text{Output of NAND gate} = \overline{A \cdot A} = \bar{A}$$
$$\text{Output of OR gate} = \bar{A} + B$$
$$Y = \overline{\bar{A} + B} = \overline{\overline{A}} \cdot \bar{B} = A \cdot \bar{B}$$
$$Y$$ is 1 for $$A =$$ and $$B = 0$$
Hence, $$Y = 1$$ for intervals $$(0,1)$$ and $$(4,5)$$, and $$0$$ elsewhere.
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
