Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
An electric train is moving at $$36\text{ kmph}$$. When its power is turned off, it stops in $$20\text{ s}$$. If the train were moving at $$54\text{ kmph}$$, find how far ahead (in m) of the station should the power be turned off, to halt the train at the station. Assume same uniform retardation in both the cases.
Correct Answer: 225
$$36\text{ kmph} = 10\text{ m/s}$$, so the retardation is $$\frac{10}{20} = 0.5\text{ m/s}^2$$. At $$54\text{ kmph} = 15\text{ m/s}$$, the stopping distance is $$\frac{v^2}{2a} = \frac{225}{1} = 225\text{ m}$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.