Question 20

A man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres and takes a right turn and moves 3 metres and then moves 3 metres in the north direction. Find the distance between his initial and his final position.

Solution

The man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres towards east and takes a right turn and moves 3 metres towards south and then moves 3 metres in the north direction.

Thus, distance between initial and final position = $$\sqrt{(24)^2+(7)^2}$$

= $$\sqrt{576+49}=\sqrt{625}=25$$ m

=> Ans - (A)

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SSC CHSL 7 Feb 2017 Morning Shift

A man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres and takes a right turn and moves 3 metres and then moves 3 metres in the north direction. Find the distance between his initial and his final position.

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