Sign in
Please select an account to continue using cracku.in
↓ →
A man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres and takes a right turn and moves 3 metres and then moves 3 metres in the north direction. Find the distance between his initial and his final position.
The man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres towards east and takes a right turn and moves 3 metres towards south and then moves 3 metres in the north direction.
Thus, distance between initial and final position = $$\sqrt{(24)^2+(7)^2}$$
= $$\sqrt{576+49}=\sqrt{625}=25$$ m
=> Ans - (A)
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
