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Question 20
A boy leaves his home. He walks 45 m in south-west direction and then 145 m in north-east direction. Then, he moves 60 m in south direction. How far is he now from his initial position?
Solution
Let the boy leaves his home from origin and walks 45 m in south-west direction and then 145 m in north-east direction. Then, he moves 60 m in south direction.
Thus, distance between his initial and final position = $$\sqrt{(100)^2-(60)^2}$$
= $$\sqrt{10000-3600}=\sqrt{6400}=80$$ m
=> Ans - (B)
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