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The distance travelled by a particle is related to time $$t$$ as $$x = 4t^2$$. The velocity of the particle at $$t = 5$$ s is
Given: $$x = 4t^2$$
Velocity: $$v = \frac{dx}{dt} = 8t$$
At $$t = 5$$ s:
$$v = 8 \times 5 = 40$$ m/s
The correct answer is Option 1: 40 m s⁻¹.
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