Sign in
Please select an account to continue using cracku.in
↓ →
In the given figure, $$FD \parallel BC \parallel AE$$ and $$AC \parallel ED$$
The value of $$x$$ is
In $$\triangle ABC$$, $$\angle C = 180^\circ - 51^\circ - 62^\circ = 67^\circ$$. Since $$AE \parallel BC$$, $$\angle EAC = \angle ACB = 67^\circ$$ (alternate angles). AEDF has both pairs of opposite sides parallel, so it is a parallelogram and its adjacent angles are supplementary. Hence $$x = 180^\circ - 67^\circ = 113^\circ$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
