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Since $$AB \parallel CD$$, both lines make the same angle $$2x^\circ$$ with the horizontal line MQ. The line MP makes $$100^\circ$$ with MQ, so the angle between AP and AB is $$100^\circ - 2x^\circ$$. This angle is marked $$3x^\circ$$, so $$100 - 2x = 3x$$, giving $$x = 20$$.
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