A train moving with a constant speed crosses a stationary pole in 4 seconds and a platform 75 m long in 9 seconds. The length of the train is (in meters)

Solution

If the train has length $$L$$ and speed $$v$$, crossing the pole gives $$L=4v$$, and crossing the platform gives $$L+75=9v$$. Substituting, $$4v+75=9v$$, so $$v=15$$ and $$L=4\times15=60$$ meters.

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