JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A person can throw a ball upto a maximum range of 100 m. How high above the ground he can throw the same ball?
$$R_{\text{max}} = \frac{u^2}{g} = 100\ \text{m} \quad \text{--- (1)}$$
$$H_{\text{max}} = \frac{u^2 \sin^2(90^\circ)}{2g} = \frac{u^2}{2g} \quad \text{--- (2)}$$
$$H_{\text{max}} = \frac{R_{\text{max}}}{2} = \frac{100}{2} = 50\ \text{m}$$
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
