A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10 m in $$t$$ s, the distance travelled by the toy in the next $$t$$ s will be:

A toy starts from rest under constant acceleration and travels 10 m in $$t$$ seconds. We need to find the distance in the next $$t$$ seconds.

Using $$s = ut + \frac{1}{2}at^2$$ with $$u = 0$$:

$$10 = \frac{1}{2}at^2 \quad \ldots (1)$$

$$s_{2t} = \frac{1}{2}a(2t)^2 = \frac{1}{2}a \cdot 4t^2 = 4 \times \frac{1}{2}at^2 = 4 \times 10 = 40 \text{ m}$$

$$s_{\text{next}} = s_{2t} - s_t = 40 - 10 = 30 \text{ m}$$

Hence, the correct answer is Option C: 30 m.