Question 198
The angle of elevation of a tower from a distance of 100 metre from its foot is 30°. Then the height of the tower is
Solution
Height of tower = AB
In $$\triangle$$ABC
=> $$tan\theta = \frac{AB}{BC}$$
=> $$tan30^{\circ} = \frac{AB}{100}$$
=> $$\frac{1}{\sqrt{3}} = \frac{AB}{100}$$
=> $$AB = \frac{100}{\sqrt{3}}$$
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