Question 190
What will come in place of both the question marks (?) In the following question ?
$$\frac{(?)^{1.6}}{96}=\frac{24}{(?)^{0.4}}$$
Solution
$$\frac{(?)^{1.6}}{96}=\frac{24}{(?)^{0.4}}$$
$$?^{1.6+0.4} = 24*96$$
$$?^{2} = 48*48$$
=> $$? = 48$$
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