Question 190

What will come in place of both the question marks (?) In the following question ?

$$\frac{(?)^{1.6}}{96}=\frac{24}{(?)^{0.4}}$$

Solution

$$\frac{(?)^{1.6}}{96}=\frac{24}{(?)^{0.4}}$$

$$?^{1.6+0.4} = 24*96$$
$$?^{2} = 48*48$$

=> $$? = 48$$


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