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Question 19

The graph which depicts the results of Rutherford gold foil experiment with $$\alpha$$-particles is:
$$\theta$$: Scattering angle
Y: Number of scattered $$\alpha$$-particles detected
(Plots are schematic and not to scale)

To determine the correct graph for the Rutherford gold foil experiment, we need to look at the relationship between the number of scattered $$\alpha$$-particles ($$Y$$) and the scattering angle ($$\theta$$).

The Physics Behind the Graph

In Rutherford's alpha-particle scattering experiment, the vast majority of $$\alpha$$-particles passed straight through the gold foil with little to no deflection. Only a very small fraction of particles experienced large deflections, and an incredibly tiny fraction (about 1 in 8,000) bounced back almost completely ($$\theta \approx 180^\circ$$).

Mathematically, Rutherford derived that the number of scattered particles $$Y$$ detected at a scattering angle $$\theta$$ is inversely proportional to $$\sin^4\left(\frac{\theta}{2}\right)$$:

$$Y \propto \frac{1}{\sin^4\left(\frac{\theta}{2}\right)}$$

Characteristics of the Correct Graph

When plotting $$Y$$ (Number of scattered $$\alpha$$-particles) versus $$\theta$$ (Scattering angle):

  • At small angles ($$\theta \to 0^\circ$$): The value of $$\sin^4\left(\frac{\theta}{2}\right)$$ is extremely small, meaning $$Y$$ is extremely large. The graph starts very high up on the Y-axis.
  • As the angle increases: The value of $$Y$$ drops exponentially and steeply.
  • At large angles ($$\theta \to 180^\circ$$): The number of particles approaches a very low, near-zero baseline, representing the rare head-on collisions.

Conclusion

The correct graph is a steeply decreasing, asymptotic curve that starts incredibly high near $$\theta = 0^\circ$$ and flattens out close to the horizontal axis as $$\theta$$ approaches $$180^\circ$$.

If your options include a graph that looks like a sharp hyperbola-like drop (extending from a very high value at low angles to a nearly flat line at high angles), that is the correct choice.

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