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General solution to the equation $$(x^3 + 3xy^2)dx + (3x^2y + y^3)dy = 0$$ is (c is a constant)
$$\frac {1}{4}(x^4 + 6x^2y^2 + y^4) = c$$
$$\frac {1}{5}(8x^4 + 6x^3 y + y^3) = c$$
$$\frac {1}{12}(x^3 + 6xy^2 + y^4) = c$$
$$(x^2 + y^2) = c$$
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Arrangement
Miscellaneous LR
Data change over a period
Charts
DI Miscellaneous
Data Interpretation Basics
Puzzles
Truth Lie Concept
Special Charts
Quant Based LR
Table with Missing values
Routes And Networks
Maxima-Minima
Quant Based DI
DI with connected data sets
Games and Tournamnents
2D & 3D LR
Data Interpretation
Scheduling
Selection With Condition
Coins and Weights
Venn Diagrams
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