A rectangular loop has a sliding connector PQ of length $$\ell$$ and resistance $$R\Omega$$ and it is moving with a speed $$v$$ as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents $$I_1, I_2$$ and $$I$$ are

A

$$I_1 = -I_2 = \frac{B\ell v}{R}, I = \frac{2 B\ell v}{R}$$

B

$$I_1 = I_2 = \frac{B\ell v}{3R}, I = \frac{2 B\ell v}{3R}$$

C

$$I_1 = I_2 = I = \frac{B\ell v}{R}$$

D

$$I_1 = I_2 = \frac{B\ell v}{6R}, I = \frac{B\ell v}{3R}$$