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Question 189
If θ be acute angle and tan (4θ - 50°) = cot(50° - θ), then the value of 9 in degrees is:
Solution
tan(90-θ)=cotθ
tan(4θ-50) = cot(90 - (4θ-50))
=cot(140-4θ)
Given tan (4θ - 50°) = cot(50° - θ)
tan (4θ - 50°) = cot(140° - 4θ)
cot(50° - θ) = cot(140° - 4θ)
50° - θ = 140° - 4θ
3θ = 90°
θ = 30°
Option D is the correct answer.
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