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If θ be acute angle and tan (4θ - 50°) = cot(50° - θ), then the value of 9 in degrees is:
tan(90-θ)=cotθtan(4θ-50) = cot(90 - (4θ-50))=cot(140-4θ)Given tan (4θ - 50°) = cot(50° - θ)tan (4θ - 50°) = cot(140° - 4θ) cot(50° - θ) = cot(140° - 4θ)50° - θ = 140° - 4θ3θ = 90°θ = 30°Option D is the correct answer.
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