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If each diode has a forward bias resistance of 25$$\Omega$$ in the below circuit, which of the following options is correct?
$$\text{Based on the } 5\text{ V source, } D_1 \text{ and } D_3 \text{ are forward-biased, while } D_2 \text{ is reverse-biased (open circuit)} $$
$$\implies I_3 = 0$$
$$R_{\text{branch1}} = R_{\text{branch3}} = 25 + 125 = 150\,\Omega \implies I_4 = I_2 = \frac{V_{\text{parallel}}}{150}$$
$$I_1 = I_4 + I_3 + I_2 = I_2 + 0 + I_2 = 2I_2 \implies \frac{I_1}{I_2} = 2$$
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