The discharge over the rectangular weir is equal to:
(a) $$\frac{2}{3Cd\sqrt{2g}LH^{\frac{3}{2}}}$$
(b) $$\frac{3}{2Cd\sqrt{2g}LH^{\frac{3}{2}}}$$
(c) $$\frac{3}{2Cd\sqrt{2g}LH^{\frac{2}{3}}}$$
(d) $$\frac{2}{3Cd\sqrt{2g}LH^{\frac{2}{3}}}$$
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