Question 171

If a 48 m tall building has a shadow of 48√3 m., then the angle of elevation of the sun is

Solution

AB = building = 48 m

BC = shadow = 48$$\sqrt{3}$$ m

$$\angle$$ACB = $$\theta$$ = ?

$$\therefore$$ tan$$\theta$$ = $$\frac{AB}{BC} = \frac{48}{48\sqrt{3}}$$

=> tan$$\theta$$ = $$\frac{1}{\sqrt{3}}$$ = tan 30°

=> $$\theta$$ = 30°

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