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If a 48 m tall building has a shadow of 48√3 m., then the angle of elevation of the sun is
AB = building = 48 m
BC = shadow = 48$$\sqrt{3}$$ m
$$\angle$$ACB = $$\theta$$ = ?
$$\therefore$$ tan$$\theta$$ = $$\frac{AB}{BC} = \frac{48}{48\sqrt{3}}$$
=> tan$$\theta$$ = $$\frac{1}{\sqrt{3}}$$ = tan 30°
=> $$\theta$$ = 30°
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