Join WhatsApp Icon JEE WhatsApp Group
Question 17

Hoffmann bromamide degradation of benzamide gives product A, which upon heating with CHCl$$_3$$ and NaOH gives product B. The structures of A and B are:

Hoffman degradation of Benzamide gives aniline. Aniline upon treatment with CHCl$$_3$$ and NaOH (carbylamine test) gives benzene carbylamine.

Get AI Help

Video Solution

video
Ask AI