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$$(?)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$
$$\sqrt{2809}$$
$$(53)^{3}$$
$$\sqrt{53}$$
53
None of these
Let the unknown quantity be 'x'.$$(x)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$.$$(x)^{1/3}+3-12=44$$.$$(x)^{1/3}=53$$.$$x=53^{3}$$.Option B is correct.
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