Question 165

$$(?)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$

Solution

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Let the unknown quantity be 'x'.
$$(x)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$.
$$(x)^{1/3}+3-12=44$$.
$$(x)^{1/3}=53$$.
$$x=53^{3}$$.
Option B is correct.

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