$$(?)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$
Let the unknown quantity be 'x'.
$$(x)^{1/3}+\sqrt{9}-12= \sqrt{1764}$$.
$$(x)^{1/3}+3-12=44$$.
$$(x)^{1/3}=53$$.
$$x=53^{3}$$.
Option B is correct.
Create a FREE account and get:
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
