Question 160

$$\sqrt{?}-12=\sqrt{1296}$$

Solution

Let the unknown term be a.

Finding square root of large numbers can be difficult.Hence we can write it in terms of its prime factors.

1296 can be written as $$2^{4} \times 3^{4}$$.

$$\sqrt{1296}$$=$$\sqrt{2^{4} \times 3^{4}}$$=$$2^{2}\times3^{2}$$

$$\sqrt{a}$$ = 36 + 12 =48

a= $$48^{2}$$.

Hence Option B is the correct answer.

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