Question 160

$$\sqrt{?}-12=\sqrt{1296}$$

Let the unknown term be a.

Finding square root of large numbers can be difficult.Hence we can write it in terms of its prime factors.

1296 can be written as $$2^{4} \times 3^{4}$$.

$$\sqrt{1296}$$=$$\sqrt{2^{4} \times 3^{4}}$$=$$2^{2}\times3^{2}$$

$$\sqrt{a}$$ = 36 + 12 =48

a= $$48^{2}$$.

Hence Option B is the correct answer.

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