Two trains are moving in the same direction at the speed of 24 km/hr and 50 km/hr. The time taken by faster train to cross a man sitting in the slower train is 72 seconds. What will be the length (in metres) of the faster train?
Let length of faster train = $$l$$ m
The trains are moving in the same direction, thus relative speed = $$50-24=26$$ km/hr = $$(26\times\frac{5}{18})=\frac{65}{9}$$ m/s
Time taken = 72 seconds
Using, distance = speed $$\times$$ time
=> $$l=72\times\frac{65}{9}=520$$ m
=> Ans - (C)
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