Question 16

Evaluate $$\left[\cos^2 \left(\frac{\pi}{32}\right) + \cos^2 \left(\frac{3 \pi}{32}\right) + \cos^2 \left(\frac{5 \pi}{32}\right) + ... + \cos^2 \left(\frac{15 \pi}{32}\right)\right] - \left[\sin^2 \left(\frac{\pi}{16}\right) + \sin^2 \left(\frac{2 \pi}{16}\right) + ... + \sin^2 \left(\frac{7 \pi}{16}\right)\right]$$

Solution

$$\cos\left(A\right)\ =\sin\left(\frac{\pi}{2}-A\right)$$

$$\sin A=\cos\left(\frac{\pi}{2}-A\right)$$

$$\cos\left(\frac{\pi}{32}\right)=\sin\left(\frac{\pi}{2}-\frac{\pi}{32}\right)=\sin\left(\frac{15\pi}{32}\right)$$

$$\sin^2\left(A\right)+\cos^2\left(A\right)=1$$

So the series simplifies to (1+1+1+1)-(1+1+1+1/2)

therefore value of series is 1/2


Create a FREE account and get:

  • All Quant Formulas and shortcuts PDF
  • 40+ previous papers with solutions PDF
  • Top 500 MBA exam Solved Questions for Free

cracku

Boost your Prep!

Download App