Question 16

250 men can finish a work in 20 days working 5hours aday. To finish the with in 10 days working 8 hours a day,the minimum number of men required is

Solution

M1 D1 T1 = M2 D2 T2

given M1 = 250 men

D1 = 20 days

T1 = 5 hours

D2 = 10 days

T2 = 8 hours

M2 = ?

substituting

$$ 250 \times 20 \times 5 = M2 \times 10 \times 8 $$

solving M2 = $$ \frac{250 \times 20 \times 5}{10 \times 8} = 312.5 $$

312.5 approximately equal to 313

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: