Question 15

Some masons promised to do a work in 10 days but 8 of them were absent and remaining did the work in 18 days. What was the original number of masons?

Solution

Let original number of masons = $$x$$

Using, $$M_1D_1=M_2D_2$$

=> $$x\times10=(x-8)\times18$$

=> $$10x=18x-144$$

=> $$18x-10x=144$$

=> $$x=\frac{144}{8}=18$$

$$\therefore$$ Original number of masons = 18

=> Ans - (D)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: