Question 15

If xy = 48 and $$x^2 + y^2$$ = 100, then (x + y) is

Solution

Given : $$(x^2 + y^2) = 100$$ and $$xy = 48$$

Using $$(x + y)^2 = x^2 + y^2 + 2xy$$

=> $$(x + y)^2 = 100 + (2 \times 48)$$

=> $$(x + y) = \sqrt{100 + 96} = \sqrt{196} = 14$$

=> Ans - (D)

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