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Question 15

If $$a + b = 1$$ and $$a \times b = 2$$, then $$a^3 + b^3 = $$

Solution

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Using $$a^3 + b^3 = (a + b)^3 - 3ab(a + b)$$ we get $$1^3 - 3 \times 2 \times 1 = 1 - 6 = -5$$.

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