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An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity $$6 \times 10^8$$ W m$$^{-2}$$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space = $$3 \times 10^8$$ m s$$^{-1}$$) :
$$v = \frac{c}{\mu} = \frac{3 \times 10^8}{3} = 10^8\text{ m s}^{-1}$$
$$P = \frac{I}{v}$$
$$P = \frac{6 \times 10^8}{10^8} = 6\text{ N m}^{-2}$$
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