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The primary side of a transformer is connected to 230 V, 50 Hz supply. The turn ratio of primary to secondary winding is 10 : 1. Load resistance connected to the secondary side is 46 $$\Omega$$. The power consumed in it is :
Primary voltage: $$V_p = 230$$ V. Turn ratio $$N_p : N_s = 10 : 1$$.
Secondary voltage: $$V_s = V_p \times \frac{N_s}{N_p} = 230 \times \frac{1}{10} = 23$$ V.
Load resistance: $$R_L = 46 \; \Omega$$.
Power consumed: $$P = \frac{V_s^2}{R_L} = \frac{23^2}{46} = \frac{529}{46} = 11.5$$ W.
The answer is $$11.5$$ W, which corresponds to Option (3).
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