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The probability of getting the sum 7 when two dice are thrown simultaneously is
$$\frac{7}{36}$$
$$\frac{5}{36}$$
$$\frac{1}{6}$$
$$\frac{5}{18}$$
Total cases when 2 dice are thrown together = 36Cases when sum is 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) i.e. 6Hence, probability = 6/36 = 1/6
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