Question 147

If A and B are independent events such that P(A) = 0.9 and P(B) = 0.8 then $$p(A \cap \overline{B}) + P(\overline{A} \cap B) =$$

Solution

p(A) = 0.9 hence, p($$\overline{\ A}$$) = 0.1
p(B) = 0.8 hence, p($$\overline{\ B}$$) = 0.2

Now, p($$A\ intersetion\overline{\ B}$$) = p(A)*p($$\overline{\ B}$$) = 0.18
Alos, p($$\overline{\ A}\ intersetion\ B$$) = p($$\overline{\ A}$$)*p(B) = 0.08
Hence, the sum of the two terms = 0.26

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AP ICET 2017

If A and B are independent events such that P(A) = 0.9 and P(B) = 0.8 then $$p(A \cap \overline{B}) + P(\overline{A} \cap B) =$$

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