Question 146

In $$\triangle$$ ABC, the internal bisectors of $$\angle$$B and $$\angle$$C meet at point D. If $$\angle$$A=$$80^\circ$$, then $$\angle$$BDC is of:

Solution

Given : D is the incentre of $$\triangle$$ ABC and $$\angle$$ BAC = 80°

To find : $$\angle$$ BDC = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{\angle A}{2}$$

=> $$\theta=90^\circ+\frac{80^\circ}{2}$$

=> $$\theta=90^\circ+40^\circ$$

=> $$\theta=130^\circ$$

=> Ans - (A)

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